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2=6+60t-16t^2
We move all terms to the left:
2-(6+60t-16t^2)=0
We get rid of parentheses
16t^2-60t-6+2=0
We add all the numbers together, and all the variables
16t^2-60t-4=0
a = 16; b = -60; c = -4;
Δ = b2-4ac
Δ = -602-4·16·(-4)
Δ = 3856
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3856}=\sqrt{16*241}=\sqrt{16}*\sqrt{241}=4\sqrt{241}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-4\sqrt{241}}{2*16}=\frac{60-4\sqrt{241}}{32} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+4\sqrt{241}}{2*16}=\frac{60+4\sqrt{241}}{32} $
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